Essay On Mental Health - 1545 Words

Exposure to DVA was high, with a mean CAS score of 56 (SD 34). The mean CORE-OM score was 18 (SD 8) with 76% above the clinical threshold (95% confidence interval: 70–81%). Depression and anxiety levels were high, with means close to clinical thresholds, and more than three-quarters of respondents recorded PTSD scores above the clinical threshold. Symptoms of mental illness increased stepwise with increasing severity of DVA. Women DVA survivors who seek support from DVA services have recently experienced high levels of abuse, depression, anxiety, and especially PTSD. Clinicians need to be aware that patients presenting with mental health conditions or symptoms of depression or anxiety may be experiencing or have experienced DVA. The high†¦show more content†¦The objectives of this study were to (1) determine the prevalence of domestic violence and childhood sexual abuse in women with HIV and women at risk for HIV infection and (2) examine the association between a his tory of childhood sexual abuse and HIV-related high-risk behaviors (Cohen, et al., 2000). Women involved with domestic abuse while young tend to contract the HIV disease when they are older because they consume their self in alcohol and drugs. Also, not using protection is a way to feel a void of being wanted because they have been hurt and abused by one or multiple people in their lives. The prevalence of self-reported abuse in this population was 39.5%. White women were significantly more likely to report any history of abuse than nonwhite women. Relationship issues were the only reason for pregnancy termination given more often by women with an abuse history than by non-abused women. Women with abuse histories were significantly less likely than non-abused women to inform the partner of the pregnancy or to have partner support for or involvement in the abortion decision. The prevalence of abuse reported by women in this population suggests that many women seeking abortion services may have abuse histories. Abused women may have different reasons for pregnancy termination than non-abused women and may be more likely to make the abortion decision without partner involvement. When routine screening for abuseShow MoreRelatedMental Health Essay768 Words   |  4 PagesIntroduction Mental health is just as important as physical health. Your ability to care for yourself, attend school and work, develop friendships, and care for your family all depend on good mental health. Some signs of poor mental health include: Problems focusing, sleeping, or eating. Anger. Irritability. Anxiety. Difficulty with relationships or discomfort in social settings. 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Analysis Of Delacour s Delacour - 1078 Words

In addition to fashionable reading, Delacour also shows a habit of reading Methodistical religious texts in her times of mental fervor. After Dr. X finds out about the books, he is â€Å"convinced that superstitious horrors hung upon his patient’s spirits, and affected her health† (Edgeworth 316). Dr. X’s ideas are born from the fact that at the time Methodistical text were â€Å"operating outside rational discourse and sociable domestic space.† They were seen to make one â€Å"vulnerable to manipulation† and cause â€Å"wrong interpretations† of daily happenings (MacFayden 436). Once again the things that Delacour reads feed into her mental state. The values that she is receiving from these texts are outside of the values that society says are acceptable to†¦show more content†¦The sickly nature of Delacour’s children points out that there could be something wrong with Delacour herself. By being connected to her, both childr en have died. The sickness the Delacour herself experiences both physically and mentally could have easily passed to her children. Their deaths not only show a connection to a sickly family line, but they also put a stress on Delacour’s mind. Even if Delacour’s health is not the reason for their deaths, there is still the possibility. Delacour is aware that she could be at fault and the guilt continues to eat away at her, heightening her emotions and clouding her mental space and judgment. Her children may not suffer from madness, but they still could cause her madness nonetheless. Not only does Lady Delacour exhibit all three of Pargeter’s proposed causes of female madness, but she also exhibits what Prageter labels as the primary symptom of madness, namely delirium. Delirium is said to occur when â€Å"the body could not distinguish the impressions of real objects from those of imagination† (Thame 276). On the night before her impending surgery, Delacour tells Belinda that figures have been appearing to her. Delacour explains, â€Å"The forms that flit before my eyes when I am between sleeping and waking,†¦I am willing to believe are the effects of opium, but, Belinda, it is impossible I should be convinced that my senses have deceived me with respect to what I have beheld when I have been as broad awake, and in perfect

Flyrock Tires Free Essays

Six Sigma Quality at Flyrock Tires Executive Summary The process of creating tires at Flyrock Tires involves 20 different steps to take the rubber from bales to final curing. Given this complexity and the high production volume (the factory produces about 10,000 tires per hour), it takes only a small margin of error in each of these steps to begin to compound and result in a high defective rate. For both public safety and their reputation, Flyrock strives to minimize the number of defects. We will write a custom essay sample on Flyrock Tires or any similar topic only for you Order Now The answers to the questions asked by this case form a good base for evaluating the production and extrusion process at Flyrock. The company begins by setting expectations for what defect rates should be under ideal conditions as well as setting expectations for defect rates when machinery has become worn out. This allows them to detect things like worn bearings in machinery. The case also begins the framework for evaluating the process from a six-sigma perspective and how this might help control defects. Under ideal conditions, the extruder should produce tires that meet specifications 98. 67% of the time, meaning only 1. 33% of tires are defective. When the bearing is worn out, the defect rate increases three-fold to 4. 7%. This means that more than one in twenty-five tire sheets is defective. If testing samples of ten sheets per hour, the machine operators could expect to find a defective every two and a half hours. In testing whether the extrusion process is in control or not, the three sigma control limits recommended by Susan Douglas will narrow the bandwidth of acceptable tires from 400  ± 10 thou to 400  ± 3. 795 thou. By implementing a stricter six-sigma system and decreasing the standard deviation, the likelihood of producing tires within acceptable levels of thickness increases to 100%. This becomes a near-perfect process. With this information, Susan Douglas should now take appropriate steps to count the actual number of defects that occur from the extrusion process. Having that will allow her to analyze if the process is actually in control, using various control charts. Using that, she will be able to adjust the process as needed to reduce the number of defective tires, improve quality and efficiency, and ultimately reduce costs for Flyrock. Question 1 The mean, confidence intervals, and standard deviation are provided to us. Mean ( µ) = 400 thou Confidence interval =  ± 10 thou Standard deviation (? ) = 4 thou This question is a simple normal probability distribution problem. It can be restated as: What is the probability that rubber sent through the extruder will be between 390 thou and 410 thou in thickness? P(390 ? x ? 410) We first need to find the z value for each boundary then find the corresponding probability in the normal distribution table: z = (x –  µ)/? z = (390-400)/4 = -2. 5 z(-2. 5) = . 0062 z = (410-400)/4 = 2. 5 z(2. 5) = . 9938 P(-2. 5 ? z ? 2. 5) = . 9938 – . 0062 = . 9867 Therefore, there is a 98. 7% probability that the rubber will be extruded with the specifications. Question 2 To find the upper and lower control limits, the following formulas apply: Upper Control Limit (UCL) =  µ + z? Lower Control Limit (LCL) =  µ – z? where ? = ? /n  µ = 400 ? = 4 n = 10 z = 3 ? = 4/10 = 1. 265 UCL = 400 + 3(1. 265) = 403. 795 LCL = 400 – 3(1. 265) = 396. 205 Question 3 If a be aring is worn out, the extruder produces a mean thickness of 403 thou even though the setting is at 400. This means that  µ has shifted to 403 and the confidence level will be lower than the 98. 7% we calculated when the bearings are not worn out. We can restate the question for number 1 to ask: What is the probability that rubber sent through the extruder will be outside 390 thou and 410 thou in thickness when the mean thickness has shifted to 403 thou? Again, we need to find the z value for each boundary then find the corresponding probability in the normal distribution table: z = (x –  µ)/? z = (390-403)/4 = -3. 25 z(1. 75) = 0. 9599 z = (410-403)/4 = 1. 75 z(-3. 25) = 0. 0006 P(-3. 25z1. 75) = 0. 9599 – 0. 0006 = 0. 9593 Therefore, there is a 95. 93% probability that the rubber will be extruded with the specifications. However to find the proportion of defective sheets we must take 1-. 9593 which gives us a defective rate of 4. 07%. Assuming the three sigma control limits of 403. 795 and 396. 205, we can calculate the probability that a sample is out of control by first calculating the percentage of in control samples. z = (x –  µ)/? z = (393. 205-403)/1. 265 = -2. 5 z(-5. 37) = 0. 0000 z = (403. 795-403)/ 1. 265= 2. 5 z(. 628) = 0. 7357 P in control (0z. 7357) = 0. 7357 P Out of control = 1-. 7357 = . 2643 = 26. 43% Using the proportion of defective units we can calculate the average time it will take to discover a worn bearing. 1/. 2643 = 3. 77 hours. On average it will take an operator about 4 hours to detect that the process is out of control. Question 4 Assuming our mean is still 400, but a new standard deviation of 1. 667 based on a six-sigma process, we find the proportion of the rubber extruded that is within our specifications by calculating the probability that rubber sent through the extruder will be outside our limits: = (x –  µ)/? P(x410) = P(z410-400/1. 667) = P(z 6. 0) = 1 — based on our normal tables P(x390) = P(z390-400/1. 667) = P(z -6. 0) = 0 — based on our normal tables To then find the probability of our extruded rubber being within specifications, we subtract P(-6. 0z6. 0) = 1 – 0 = 1, meaning that 100%  of the rubber extruded is within our specifications. Question 5 Similar to question #2, to f ind the upper and lower control limits, the following formulas apply: Upper Control Limit (UCL) =  µ + z? Lower Control Limit (LCL) =  µ – z? where ? = ? /n  µ = 400 ? = 1. 667 z = 3 ? = 1. 667/10 = . 527 UCL = 400 + 3(. 527) = 401. 581 LCL = 400 – 3(. 527) = 398. 419 While these new control limits are very similar, they do narrow our range which should lead to less defects. Question 6 Assuming that we return to the case of the worn bearing in question 3 where extrusion produces a mean thickness of 403 thou even though the setting is 400 thou. , we find that the proportion of defective sheets under a six-sigma process equals 0%. P(x410) = P(z410-403/1. 67) = P(z4. 199) = 1 P(x390) = P(z390-403/1. 667) = P(z-7. 8) = 0 P(-7. 8z4. 2) = 1 – 0 = 1 Proportion of defective sheets =  Ã‚  0% Looking at the control limits in question 5 we can find the probability that a sample taken from the extruder with the worn bearings will be out of control: We begin by finding the probability of the samples being â€Å"in control†: P(In Control) = P(396. 837x403. 163) P((398 . 419-403)/0. 527x(401. 581-403)/0. 527), which equals P(-8. 69z-2. 69) = 0. 0036 We can then subtract by one to find the probability of being out of control: P(Out of Control) = 1 – 0. 0036 = 0. 9964 This tells us that based on the control limits from question #5, the probability of a defect under a six-sigma process with worn bearings is 99. 64%. Assuming that the six-sigma process produces no defects, the likelihood of the sampling each hour finding a defect is 0%. If we assume our control limits discussed previously with a worn bearing and a defect probability of 99. 64%, we would find a defect in the first hour based on a sample size of 10. How to cite Flyrock Tires, Essay examples